Answer:
The correct option is 4. The solution of given system of equation is (3,-1), which lies in 4th quadrant.
Step-by-step explanation:
The given equations are
\(x-3y=6\) .... (1)
\(x+y=2\) .... (2)
Subtract equation (2) from equation (1).
\(x-3y-(x+y)=6-2\)
\(x-3y-x-y=4\)
\(-4y=4\)
Divide both sides by -4.
\(y=-1\)
The value of y is -1.
Substitute y=-1 in equation (1).
\(x-3(-1)=6\)
\(x+3=6\)
Subtract 3 from both sides.
\(x=6-3\)
\(x=3\)
The solution of given system of equation is (3,-1).
Since the x coordinate is positive and y coordinate is negative, therefore the solution of given system of equation lies in 4th quadrant.
