Answered

Given △JKL, sin(38°) equals



cos(38°).


cos(52°).


tan(38°).


tan(52°).

Given JKL, sin(38 ) equals cos(38 ). cos(52 ). tan(38 ). tan(52 ). class=

Verified Answer :

carlosego

By definition, we have to:

\(sin(x) = \frac{C.O}{h}\)

\(cos(x) = \frac{C.A}{h}\)

Where,

x: angle

C.O: opposite leg

C.A: adjacent leg

h: hypotenuse

Using the definitions we have that for sin (38 °):

\(sin(38) = \frac{KJ}{KL}\)

Then, we have the following trigonometric relationship:

\(cos(52)= \frac{KJ}{KL}\)

Therefore, it is true that:

Sin(38) = cos(52)

Answer:

Given △JKL, sin(38°) equals:


cos(52°).

The value of Sin(38°) is equal to Cos(52°).

What are Trigonometric functions?

\(Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\)

\(Cos \theta=\dfrac{Base}{Hypotenuse}\)

\(Tan \theta=\dfrac{Perpendicular}{Base}\)

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

Given to us

  • ∠K = 52°,
  • ∠L = 38°

In △JKL

1. For ∠L

\(Sin (\angle L) = \dfrac{Perpendicular}{Hypotenuse}\)

Substituting the values,

\(Sin (38^o) = \dfrac{KJ}{KL}\)

Therefore, we need to find the value of another ratio that is equal to \(\dfrac{KJ}{KL}\).

2. For ∠K

\(Cos (\angle K) = \dfrac{Base}{Hypotenuse}\)

Substituting the values,

\(Cos (52^o) = \dfrac{KJ}{KL}\)

Hence, the value of Sin(38°) is equal to Cos(52°).

Learn more about Trigonometric functions:

https://brainly.com/question/6904750

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