Answer : The energy of exactly one photon of this light is \(4.64\times 10^{-19}J\)
Explanation : Given,
Frequency of blue light = \(7.00\times 10^{14}Hz=7.00\times 10^{14}s^{-1}\)
Formula used :
\(E=h\times
u\)
where,
\(u\) = frequency of light
h = Planck's constant = \(6.626\times 10^{-34}Js\)
Now put all the given values in the above formula, we get:
\(E=(6.626\times 10^{-34}Js)\times (7.00\times 10^{14}s^{-1})\)
\(E=4.64\times 10^{-19}J\)
Therefore, the energy of exactly one photon of this light is \(4.64\times 10^{-19}J\)
