Brainiacsteph
Answered

three nails have a mass of 3.05 g. how many moles of iron do the contain?

Verified Answer :

dexteright02

Data:
3 nails of iron = 3.05 g (by nail)

The atomic mass of iron is 55.845 amu, so the molar mass is:
M = 55.845 → M ≈ 56 g / mol

 
With a simple 3 rule:

56 g → 1 mol
3.05 g → y mol

Portanto:
\(\frac{56}{3.05} = \frac{1}{y}\)

\(56*y = 1*3.05\)
\(56y = 3.05\)
\(y = \frac{3.05}{56}\)
\(\boxed{y = 0.05446... mol}}\)

Soon:
3 nails → 3*0.05446... = 0.1638...mols 

Answer: 0.05 moles

Explanation: According to Avogadro's law, 1 mole of every substance contains Avogadro's number of particles and weighs equal to the molar mass of the substance.

\(Moles=\frac{\text{Given mass}}{\text{Molar mass}}\)

Given mass = 3.05 g

Molar mass of iron = 56 g/mol

\(Moles=\frac{3.05g}{56g/mol}=0.05moles\)

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