Verified Answer :

\(\dfrac{f(x)}{g(x)}=\dfrac{(x+1)-1}{x-2}=\dfrac{x}{x-2}\\\\ D:x-2 ot=0\\ D:x ot=2\\ D:x\in\mathbb{R}\setminus\{2\}\)

Answer: A

Step-by-step explanation: