Verified Answer :

I think the solution you are looking for is this :

\(224\quad =\quad 7\cdot 32\\ \\ \frac { 224 }{ 7 } =\frac { 7\cdot 32 }{ 7 } \\ \\ \frac { 7\cdot 32 }{ 7 } =\quad \frac { 7 }{ 7 } \cdot 32\quad =\quad 1\cdot 32=\quad 32\)

\(\frac { 224 }{ 7 } \\ \\ =\frac { 1 }{ 7 } \left( 224 \right)\)

\(\\ \\ =\frac { 1 }{ 7 } \left( 210+14 \right) \\ \\ =\frac { 210 }{ 7 } +\frac { 14 }{ 7 } \\ \\ =30+2\\ \\ =32\)