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You mix 340 grams of MgBr2 with 8 kg of water. What is the molality of your solution?

Verified Answer :

Given mass of solute = 340 gram
Molar mass of solute(MgBr2) = 184 g

Number of moles = Given mass / Molar mass = 340 / 184 = 1.85 moles

Now, Molarity = Number of moles / solution (in litres)

So, M = 1.85 / 8
M = 0.23 M

In short, Your Molarity would be: 0.23 M

Hope this helps!

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