What is the slope of a line perpendicular to the line whose equation is 2y=-6x+8
1)-3
2)1/3
3)1/6
4)-6
2y=-6x+8
First, the slope of any equation, is always the coefficient with the variable "x".
So, the slope for this line, is -6x.
To get rid of the coefficient with y, we need to divide 2, from both sides of the equal sign.
2y=-6x+8
2
y=-3+4
Now that we have our new equation, we can see that the slope of our line has also changed, from -6x to-3x. Because -6÷2=-3.
And to find the perpendicular slope, you change the reciprocal of the slope so from -3 to 1/-3 and then you change the sign of the slope so from 1/-3 to 1/3. That is your final answer.
The answer is 2) 1/3.
Your supposed to get Y by its self. So do this- (-6x+8)/2
You should get y=-3x+4
So the slope would be -3 of the original line.
The perpendicular slope would be the reciprical and opposite sign of it, so it should be 1/3
. hope this helps