There are 3.99 moles of Helium atoms in 2.4×10²⁴
From a detailed understanding of Avogadro's hypothesis, we understood that:
6.02×10²³ atoms = 1 mole of any substance
Thus,
6.02×10²³ atoms = 1 mole of Helium
With the above information in mind, we can obtain the number of mole of helium that contains 2.4×10²⁴ atoms. This can be obtained as follow:
6.02×10²³ atoms = 1 mole of Helium
Therefore,
2.4×10²⁴ atoms = \(\frac{2.4*10^{24}}{6.02*10^{23} } \\\\\\\)
2.4×10²⁴ atoms = 3.99 moles of Helium
Thus, 2.4×10²⁴ atoms are present in 3.99 moles of Helium.
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