The lengths of the corresponding sides of 2 similar right triangles are in the ratio of 2:5. If the hypotenuse of the smaller triangle is 5 inches long, how many inches long is the hypotentuse of the larger triangle?
Since the ratio is 2:5, it could be written as a fraction: 2/5. To make this apply to the sides of the triangles you'd have to create an equation where 2/5 equals 5/x, x being the length of the hypotenuse.
2/5 = 5/x
To get from 2 to 5, you'd have to multiply 2 by 2.5. Therefore, in order to make the equation equal, you have to multiply 5 (the denominator of 2/5) by 2.5.
2/5 = 5/12.5
The hypotenuse would be 12.5 inches long.
Using a rule of three, it is found that the hypotenuse of the larger triangle is 12.5 inches long.
---------------------------
2 inches - 5 inches
5 inches - x inches
Applying cross multiplication:
\(2x = 25\)
\(x = \frac{25}{2}\)
\(x = 12.5\)
The hypotenuse of the larger triangle is 12.5 inches long.
A similar problem is given at https://brainly.com/question/23536327