1/f=1/a+1/b solve for f
1/f = 1/a+1/b
RHS= b+a/ab (taking LCM)
Cross-multiplication: 1/f=a+b/ab
=>ab=(a+b)f
=>f=ab/a+b
Answer:
The value of the equation is \(f=\frac{ab}{b+a}\).
Step-by-step explanation:
Consider the provided equation.
\(\frac{1}{f}=\frac{1}{a}+\frac{1}{b}\)
We need to solve the provided equation for f.
Find the least common multiplier.
Multiply by LCM = a b f
\(\frac{1}{f}abf=\frac{1}{a}abf+\frac{1}{b}abf\)
\(f\left(b+a\right)=ab\)
Divide both sides by b+a.
\(\frac{f\left(b+a\right)}{b+a}=\frac{ab}{b+a}\)
\(f=\frac{ab}{b+a}\)
Hence, the value of the equation is \(f=\frac{ab}{b+a}\).