Answer:
\((4 \pi+26)\ in\)
Step-by-step explanation:
we know that
The perimeter of the figure is equivalent to the perimeter of a rectangle plus the perimeter of semicircle minus the length side of \(8\) inches
step 1
Find the perimeter of rectangle
the perimeter of rectangle is equal to
\(P=2(b+h)\)
we have
\(b=8\ in\)
\(h=9\ in\)
substitute
\(P=2(8+9)=34\ in\)
step 2
Find the circumference of semicircle
the of circumference of semicircle is equal to
\(C=\frac{1}{2}\pi D\)
we have
\(D=8\ in\)
substitute
\(C=\frac{1}{2}\pi (8)=4 \pi\ in\)
step 3
Find the perimeter of the figure
\(34\ in+4 \pi\ in-8\ in=(4 \pi+26)\ in\)
