Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five.


38 and 40

40 and 42

42 and 44

Verified Answer :

40 and 42..................

Answer:

The correct option is 2. The consecutive even numbers are 40 and 42.

Step-by-step explanation:

Let the two consecutive even numbers be x and x+2.

It is given that the difference of one-half the larger number and two-fifths the smaller number is equal to five.

\(\frac{1}{2}(x+2)-\frac{2}{5}(x)=5\)

\(\frac{x+2}{2}-\frac{2x}{5}=5\)

\(\frac{5x+10-4x}{10}=5\)

\(x+10=50\)

\(x=50-10\)

\(x=40\)

The value of x is 40. Therefore the two consecutive even numbers are 40 and 42.

Option 2 is correct.