A box has a length of 6 inches, a width of 8 inches, and a height of 24 inches. Can a cylindrical rod with the length of 63.5 centimeters fit in the box?
6 inches = 15.24
cm length
8 inches = 20.32
cm width
24 inches = 60.96
cm height
The diagonal along the side of the box = 20.32^2 + 60.96^2 =
4,129.024
square root
(4,129.024)
= 64.257 so the rod will fit diagonally.
Answer:
Yes, the rod can fit in the box
Step-by-step explanation:
First we have to convert the given size in inches to centimeters
1 inch = 2.54 centimeters
Length of the box = 6 × 2.54 = 15.24 cm
Width of the box = 8 × 2.54 = 20.32 cm
Height of the box = 24 × 2.54 = 60.96 cm
The longest diagonal in the box is the line between one of the top corners to the opposite bottom corner.
Calculate the length of the longest diagonal in the box:
\(\sqrt{(20.32^{2}+60.96^{2} ) }\)
= \(\sqrt{4129.024}\)
= 64.257 cm.
Therefore, a cylindrical rod with the length of 63.5 centimeters can fit in the box.