A box has a length of 6 inches, a width of 8 inches, and a height of 24 inches. Can a cylindrical rod with the length of 63.5 centimeters fit in the box?

Verified Answer :



6 inches = 15.24


cm length
8 inches = 20.32
cm width


24
inches = 60.96



cm height

The diagonal along the side of the box = 20.32^2 + 60.96^2 =



4,129.024




square root
(4,129.024)

= 64.257 so the rod will fit diagonally.
 



Answer:

Yes, the rod can fit in the box

Step-by-step explanation:

First we have to convert the given size in inches to centimeters

1 inch = 2.54 centimeters

Length of the box = 6 × 2.54 = 15.24 cm

Width of the box = 8 × 2.54 = 20.32 cm

Height of the box = 24 × 2.54 = 60.96 cm

The longest diagonal in the box is the line between one of the top corners to the opposite bottom corner.

Calculate the length of the longest diagonal in the box:

\(\sqrt{(20.32^{2}+60.96^{2} ) }\)

= \(\sqrt{4129.024}\)

= 64.257 cm.

Therefore, a cylindrical rod with the length of 63.5 centimeters can fit in the box.