A solution with pH of 9 has [OH-] concentration of
pH = -log([H+])[H+] = 10^(-pH)[H+] = 10^(-9)[H+][OH-] = KwKw = 1.010^-14 at 25 degrees celsius.[OH-] = Kw/[H+] = (1.010^-14)/(110^-9) = 1.010^-5The concentration of OH- ions is 1.0*10^-5 M.