Answer: 1040 feet.
Step-by-step explanation:
We know that , Perimeter of a rectangle = 2 (length +width)
As per given , we have
Length of football ground = \(53\dfrac{1}{3}\text{yards}=\dfrac{53\times3+1}{3}\text{yards}=\dfrac{160}{3}\text{ yards}\)
Width = 120 yards
Since, the football ground is rectangle in shape.
Then , Perimeter of the ground = \(2(\dfrac{160}{3}+120)\) yards
\(=2(\dfrac{160+3(120)}{3})\) yards
=\(2(\dfrac{160+360}{3})\)yards
\(=2(\dfrac{520}{3})\) yards
\(=\dfrac{1040}{3}\) yards
Also, 1 yard =3 feet
i.e. Perimeter = \(\dfrac{1040}{3}\times3=1040\) feet
Hence, the required perimeter is
