Knowing that: (Equation to find the pH of a solution) \(pH = -log[H+]\) Solving: \(pH = -log[H+]\) \(5.2 = - log [H+]\) Knowing that the exponential is the opposite operation of the logarithm, then we have: \([H+] = 10^{-5.2}\) \(\boxed{\boxed{[H+] = 6.30*10^{-6}}}\end{array}}\qquad\quad\checkmark\)