simplify each equation, then solve. 1) log 2 128=x
\(l[tex]log_{2}128=x\\\\ Formula\ for\ log:\\ log_{a}c=b\ \ \ =>\ a^b=c\\\\ 2^x=128\\\\ 2^x=2^7\\\\ x=7\\\\Solution\ is\ x=7.\)[/tex]
\(\log _{ 2 }{ 128 } =x\\ \\ \log _{ 2 }{ \left( { 2 }^{ 7 } \right) } =x\\ \\ 7\cdot \log _{ 2 }{ 2 } =x\)\(\\ \\ 7\cdot 1=x\\ \\ \therefore \quad x=7\)
