betzabeth8
Answered

Find an equation of the tangent line to the curve at the given point.

y = 4e^x + x, (0, 4)

Verified Answer :

LammettHash

\(y=4e^x+x\implies y'=4e^x+1\)

At the point (0,1), the derivative has the value of \(y'=4e^0+1=5\), so this is the slope of the tangent line. The equation for the line is then

\(y-4=5(x-0)\implies y=5x+4\)