Answer : The pressure of the gas is, \(6.66\times 10^{1}atm\)
Solution :
Using ideal gas equation,
\(PV=nRT\)
where,
n = number of moles of gas = 4.8 moles
P = pressure of the gas = ?
T = temperature of the gas = \(31^oC=273+31=304K\)
R = gas constant = 0.0821 Latm/moleK
V = volume of gas = 1.8 L
Now put all the given values in the above equation, we get the pressure of the gas.
\(P\times (1.8L)=4.8moles\times 0.0821L.atm/mole.K\times 304K\)
\(P=66.6atm=6.66\times 10^{1}atm\)
Therefore, the pressure of the gas is, \(6.66\times 10^{1}atm\)
