find the area of a triangle when a=78 degrees b=14 c=12
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Area=1/2.b.c.sinA
Area=1/2.14.12.sin78
Area=84.0,97
Area=82,1
Hence, the area of the triangle will be - 82.32 square units.
We have a triangle with ∠A =78 degrees, b = 14, c = 12.
We have to find the area of this triangle.
The formula to calculate the area of this triangle is -
Area = \(\frac{1}{2}\times b\times c\times sin\alpha\)
According to the question -
b = 14 units
c = 12 units
∠A =78 degrees
Therefore, using the formula discussed above, we get -
Area = \(\frac{1}{2}\) x 14 x 12 x sin (78) = 7 x 12 x 0.98 = 82.32 square units.
Hence, the area of the triangle will be - 82.32 square units.
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