What is the length of the line segment with endpoints (−3,8) and (7, 8) ? Enter your answer in the box
Length = √(y2-y1)² + (x2-x1)²
l = √(8-8)² + (7+3)²
l = √10²
l = 10
In short, Your Answer would be 10 units
Hope this helps!
Answer:
10 units
Step-by-step explanation:
\((x_1,y_1)=(-3,8)\)
\((x_2,y_2)= (7, 8)\)
We are supposed to find the length of the line segment with endpoints (−3,8) and (7, 8)
We will use distance formula : \(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)
Substitute the values :
\(d=\sqrt{(7+3)^2+(8-8)^2}\)
\(d=\sqrt{100}\)
\(d=10\)
Hence the length of the line segment with endpoints (−3,8) and (7, 8) is 10 units