What is the length of the line segment with endpoints (−3,8) and (7, 8) ? Enter your answer in the box

Verified Answer :

Length = √(y2-y1)² + (x2-x1)²
l = √(8-8)² + (7+3)²
l = √10²
l = 10

In short, Your Answer would be 10 units

Hope this helps!

Answer:

10 units

Step-by-step explanation:

\((x_1,y_1)=(-3,8)\)

\((x_2,y_2)= (7, 8)\)

We are supposed to find the length of the line segment with endpoints (−3,8) and (7, 8)

We will use distance formula : \(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Substitute the values :

\(d=\sqrt{(7+3)^2+(8-8)^2}\)

\(d=\sqrt{100}\)

\(d=10\)

Hence the length of the line segment with endpoints (−3,8) and (7, 8) is 10 units