When 1,250^3/4 is written in simplest radical form, which value remains under the radical?
Answer: The value remains under the radical is 8.
Explanation:
Given that,
\(1250^{\frac{3}{4}}\)
We know that,
\(a^{\frac{x}{n}}=n\sqrt{a^x}\)
Here, n = integer number
n is greater than x.
a = real number
Therefore,
\(1250^{\frac{3}{4}}=\sqrt[4]{1250}^3\)
\(1250^{\frac{3}{4}}=\sqrt[4]{2.5^{4}}^3\)
\(1250^{\frac{3}{4}}=5^3\sqrt[4]{2}^3\)
\(1250^{\frac{3}{4}}=125\sqrt[4]{8}\)
Hence, The value remains under the radical is 8.
Based on the steps of simplifying numbers, the value which remains under the radical after simplifying is 8.
In simplifying the expression, the following steps are taken:
1250^3/4 = \(\sqrt[4]{1250}^{3}\)
1250^3/4 = \(\sqrt[4]({2 * 5^4} )^3\)
1250^3/4 = \(5^3 * \sqrt[4]{2^3}\)
1250^3/4 = \(125 * \sqrt[4]{8}\)
Therefore, the value which remains under the radical after simplifying is 8.
Learn more about simplification of numbers at: https://brainly.com/question/481658