Answer:
\(8\frac{7}{8}\)
Step-by-step explanation:
It has been given that you want to place \(9\frac{3}{4}\) inch towel bar in the center of a door that is \(27\frac{1}{2}\) wide.
First of all, we will find the total space left on both sides of towel bar by subtracting \(9\frac{3}{4}\) from \(27\frac{1}{2}\).
\(27\frac{1}{2}-9\frac{3}{4}\)
\(\frac{27*2+1}{2}-\frac{9*4+3}{4}\)
\(\frac{54+1}{2}-\frac{36+3}{4}\)
\(\frac{55}{2}-\frac{39}{4}\)
Let us have a common denominator.
\(\frac{55*2}{2*2}-\frac{39}{4}\)
\(\frac{110}{4}-\frac{39}{4}\)
\(\frac{110-39}{4}\)
\(\frac{71}{4}\)
Now, we will divide \(\frac{71}{4}\) by 2 to find the space left on each side of the towel bar.
\(\frac{71}{4}\div 2\)
\(\frac{71}{4}\div \frac{2}{1}\)
By flipping the second fraction and multiplying by 1st fraction we will get,
\(\frac{71}{4}\times \frac{1}{2}\)
\(\frac{71}{8}\)
\(8\frac{7}{8}\)
Therefore, \(8\frac{7}{8}\) inch of space will be on each side of the towel bar.
