How do you do 4x^2+3x-10=0
\(4x^2+3x-10=0\\ 4x^2+8x-5x-10=0\\ 4x(x+2)-5(x+2)=0\\ (4x-5)(x+2)=0\\ x=\dfrac{5}{4} \vee x=-2\)