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BabieeGurl BabieeGurl
  • 05-04-2014
  • Mathematics
Answered

Suppose an investment of $1,800 doubles in value every 7 years. How much is the investment worth after 42 years?

Verified Answer :

runescapememo8 runescapememo8
  • 05-04-2014

x=2^n(1800)
x=2^6(1800)
x=$115,200

Answer Link
SociometricStar
SociometricStar SociometricStar
  • 16-03-2019

Answer:

The investment in 42 years will become $115199.88

Step-by-step explanation:

Let the investment model is @@MATH_TOKEN_0@@

A = final amount

P = initial amount

r = rate

t = time

Now, given that

P = $1800

A = 2P = 2×1800 = $3600

t = 7 years

@@MATH_TOKEN_1@@

Now, we have to find A for t = 42 years

@@MATH_TOKEN_2@@

Hence, the investment in 42 years will become $115199.88

Answer Link

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