The elastic potential energy (Ep) is given by \(Ep = \frac{1}{2}*k*x^2\)
Data:
Ep = ? (Joule)
k = 20 N/m
x (displacement) = 0.20 m
Solving:
\(Ep = \frac{1}{2}*k*x^2\)
\(Ep = \frac{1}{2}*20*0.20^2\)
\(Ep = \frac{20*0.04}{2}\)
\(Ep = \frac{0.8}{2}\)
\(\boxed{\boxed{Ep = 0.4\:J}}\end{array}}\qquad\quad\checkmark\)
