Answer:
The Maximum value of f(x)=sin(x) is 1 , when \(\theta = 90^{\circ}\)
Step-by-step explanation:
Property of Sine function:
- \(\sin \theta =0\) when \(\theta = 0^{\circ} ,180^{\circ}, 360^{\circ}\)
- Maximum value of \(\sin \theta\) is 1 , when \(\theta = 90^{\circ}\)
- Minimum value of \(\sin \theta\) is -1 , when \(\theta = 180^{\circ}\)
- Range of values of \(\sin \theta\) is \(-1\leq \sin \theta \leq 1\)
Given: f(x) = sin(x)
Then, by the property of sine function:
Maximum value of f(x) is 1 , when \(\theta = 90^{\circ}\)
