Answer:
The period of \(f(x)=\sin x\text{ is }2\pi\)
Step-by-step explanation:
Given : \(f(x)=\sin x\)
To find : The period of f(x)?
Solution :
Period is define as the value that repeat itself at regular interval.
We know that general form of sin function is
\(y=a\sin\ (bx+c)+d\)
Where,
\(\text{Period}=\dfrac{2\pi}{|b|}\)
Now, We have given
\(f(x)=\sin x\)
where, b=1
So, period will be
\(\text{Period}=\dfrac{2\pi}{|1|}\\\\\text{Period}=\dfrac{2\pi}{1}\\\\\text{Period}=2\pi\)
Therefore, The period of \(f(x)=\sin x\text{ is }2\pi\)
