Simple...
you have: \(2 x^{2} +6x=5\)
Remember, you must first move all terms to the left to reduce.
--->>
\(2x^{2} +6-5=0\)
Using \((\frac{b}{2} ) ^{2}\) in order to create a new term, and then solve for x by completing the square with this term-->>
x= \(- \frac{3}{2}, (+/-) \frac{ \sqrt{19} }{2}\)
Thus, your answer.
