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What are the coordinates of vertex J of the pre-image?(14 POINTS. PLS HELP, GEOMETRY)


Quadrilateral JKLM was dilated according to the rule

DO,1/2 (x,y)( 1/2x1/2y) to create the image quadrilateral J'K'L'M', which is shown on the graph.

A(0, -4)

B(0, -1)

C(0, 0)

D(0, 4)

What are the coordinates of vertex J of the pre-image?(14 POINTS. PLS HELP, GEOMETRY) Quadrilateral JKLM was dilated according to the rule DO,1/2 (x,y)( 1/2x1/2 class=

Verified Answer :

morgeron

If we look at where it is now, we would have multiplied the x and y values by 1/2. since we are working backwards, lets multiply by 2 instead...giving us the vertex for the pre-image....

J is now (0, -2)      multiply by 2
J was     (0, -4)

frika

If quadrilateral JKLM was dilated with scale factor 1/2 and center of dilation at origin to form quadrilateral J'K'L'M', then when you dilate quadrilateral J'K'L'M' with scale factor 2 and center of dilation at origin, you obtain quadrilateral JKLM.

The coordinates of quadrilateral J'K'L'M' are:

J'(0,-2), K'(3,2), L'(6,-2) and M'(3,-6).

Then the coordinates of quadrilateral JKLM are:

J(0,-4), K(6,4), L(12,-4) and M(6,-12).

Answer: correct choice is A: J(0,-4).

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