Answer:
The quotient is 3x+4
Step-by-step explanation:
Given the dividend and divisor i.e we have to find the quotient if \(6x^2+23x+20\) is divided by 5+2x
Given dividend is
\(6x^2+23x+20\)
⇒ \(6x^2+15x+8x+20\)
⇒ \(3x(2x+5)+4(2x+5)\)
⇒ \((3x+4)(2x+5)\)
Hence, the given dividend can written in two factors.
Now, \(\frac{6x^2+23x+20}{5+2x}=\frac{(3x+4)(2x+5)}{2x+5}=3x+4\)
Hence, the quotient is 3x+4
