A student sets up a reaction and calculates a possible yield of 55.9 grams of silver. If the student performs the reaction and the mass of actual silver obtained is 42.5 grams, what is the percent yield?
Answer : The percent yield of silver is, 76.02 %
Explanation : Given,
Theoretical yield of silver = 55.9 g
Actual yield of silver = 42.5 g
Formula used :
\(\%\text{ yield of silver}=\frac{\text{Actual yield of silver}}{\text{Theoretical yield of silver}}\times 100\)
Now we put all the given values in this formula, we get the percent yield of silver.
\(\%\text{ yield of silver}=\frac{42.5g}{55.9g}\times 100=76.02\%\)
Therefore, the percent yield of silver is, 76.02 %