In the following reaction, how many grams of ferrous sulfide (FeS) will produce 0.56 grams of iron (III) oxide (Fe2O3)? 4FeS + 7O2 → 2Fe2O3 + 4SO2 The molar mass of ferrous sulfide is 87.92 grams and that of iron (III) oxide is 159.7 grams.
You take the given mass of iron (III) oxide times the moles of FeS times the molar mass of FeS divided by the molar mass of iron (III) oxide times the moles of iron (III) oxide.
