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Instructions:Type the correct answer in each box. Round your answers to the nearest hundredth.


A ball with a mass of 1.5 kilograms is tied to the end of a rope. The ball is pulled to a height of 0.5 meters above the ground and released.


The ball has ___ joules of potential energy at position B. At position A, all of the energy changes to kinetic energy. The velocity of the ball at position A is ___

meters/second. Assume there’s no air resistance. Use g = 9.8 m/s2 , PE = m × g × h, and .

Verified Answer :

eliasbeast40

42 fiths of everything

Answer:

7.35 Joule, 3.13 m/s

Explanation:

The energy possessed by the position of the body is called potential energy of the body.

The formula for the potential energy is given by

P.E = m g h

Here, m = 1.5 kg, g = 9.8 m/s^2, h = 0.5 m

So, potential energy at B

P.E. = 1.5 x 9.8 x 0.5 = 7.35 Joule

The potential energy at B is converted into kinetic energy at point A.

\(m g h = 0.5  m v^{2}\)

\(v = \sqrt{2gh}\)

v = \sqrt{2 \times 9.8\times 0.5}

v = 3.13 m/s

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