Verified Answer :
First, evaluate the given polynomial X2+4X-12. We can check the error if performed complete factoring solution and compare the result to Mia's answer. We need to replace 4X with 6X-2X, the polynomial will become X2+6X-2X-12. Proceed with grouping of terms such as (X2+6X) -(2X+12). Then factor common value for each group such as the result become an X (X+6) -2 (X+6). For the second time, we can proceed with grouping of terms such as the result become (X+6) (X-2). We can conclude that Mia is incorrect in the last step.
Mia made mistake in the last step is factoring the polynomial \(x^{2} +4x-12\).
Given that,
Polynomial = \(x^{2} +4x-12\)
We have to find,
Mia is factoring the polynomial. she uses the steps did Mia make error.
According to the question,
First, evaluate the given polynomial \(x^{2} +4x-12\).
We can check the error if performed complete factoring solution.
Compare the result to Mia's answer.
We need to replace 4x with 6x - 2x and,
The polynomial will become \(x^{2} +6x-2x-12\)
Proceed with grouping of terms such as (\(x^{2} +6x\)) -(2x+12).
Then,
Factor common value for each group such as the result become an X (x+6) -2 (x+6).
For the second time
Proceed with grouping of terms such as the result become (x+6) (x-2).
We can conclude that Mia is incorrect in the last step.
Hence, Mia made mistake in the last step is factoring the polynomial \(x^{2} +4x-12\).
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