Verified Answer :

Al(OH)3+3H+3Br=Al+3Br+H2O. Cancel 3Br both sides
Al(OH)3+3H=Al+2H2O

Answer:

  \(Al(OH)_{3}(s)+3H^{+}(aq.)=Al^{3+}(aq.)+3H_{2}O(l)\)

Explanation:

  • Net ionic equations are written by omitting same ions present in both side of total ionic equation.
  • HBr and \(AlBr_{3}\) are strong electrolytes. Therefore they are fully dissociated in aqueous solution.
  • Total ionic equation: \(Al(OH)_{3}(s)+3H^{+}(aq.)+3Br^{-}(aq.)=Al^{3+}(aq.)+3Br^{-}(aq.)+3H_{2}O(l)\)
  • Net ionic equation (by omitting \(Br^{-}\) from both side):

              \(Al(OH)_{3}(s)+3H^{+}(aq.)=Al^{3+}(aq.)+3H_{2}O(l)\)

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