Answer:
Explanation:
Calculate the molar mass of the \(N_{2}O\):
Molar mass N = \(14\frac{g}{mol}\)
Molar mass O = \(16\frac{g}{mol}\)
Molar mass \(N_{2}O\) = 2*(Molar mass of N) + Molar mass of O
Molar mass \(N_{2}O\) = \(2*(14\frac{g}{mol})+16\frac{g}{mol}\)
Molar mass \(N_{2}O\) = \(44\frac{g}{mol}\)
Calculate the number of moles of N in 0.241g of \(N_{2}O\):
\(0.241gN_{2}O*\frac{1molN_{2}O}{44gN_{2}O}*\frac{2molesN}{1molN_{2}O}=0.01molesN\)
