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A metal ball of mass 100 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 2.5 kJ. Another metal ball of mass 200 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 5.0 kJ. What can be concluded from the data?

Verified Answer :

soooobored

specific heat (\(C_p\)) - the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree)

the equation related to this theory is
\(Q=mC_p \Delta T\)

Where Q is the energy gained or lost from the system
m is the mass of the object
\(C_p\) is the specific heat of the material
\(\Delta T\) is the change in temperature

danieladedara

Answer:

The balls are made of the same material.

Step-by-step explanation:

got it right :)

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