What is the area of this figure? Enter your answer as a decimal in the box. cm² A parallelogram with a length of 11 cm. A triangle atop the parallelogram has a short leg measuring 7 cm. A right triangle created inside the parallelogram has a long leg measuring 9 cm.
Answer:
The area of the figure is \(137.5\ cm^{2}\)
Step-by-step explanation:
we know that
The area of the figure is equal to the area of parallelogram plus the area of the triangle atop the parallelogram
Step 1
Find the area of parallelogram
The area of parallelogram is equal to
\(A=bh\)
we have
\(b=11\ cm\)
\(h=9\ cm\)
substitute
\(A=11*9=99\ cm^{2}\)
Step 2
Find the area of the triangle atop the parallelogram
The area of the triangle is equal to
\(A=\frac{1}{2}bh\)
we have
\(b=11\ cm\)
\(h=7\ cm\)
substitute
\(A=\frac{1}{2}(11)(7)=38.5\ cm^{2}\)
therefore
The area of the figure is equal to
\(99\ cm^{2}+38.5\ cm^{2}=137.5\ cm^{2}\)