Verified Answer :

Amena2000

a)
Triangle ABX
 Height = 8m
 Base = 26-11 m

Find length by  AB^2 = 15^2 + 8^2

b) Find AC by using AB as Height and BC as base
           AC^2 = AB ^2 + BC ^2
A8^2+15^2=289
Square root 289= 17cm

B) 17^2+12^2= 433
Square root 433= 20.8cm

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