Answer:
0.6
Step-by-step explanation:
Given :
Numerator is: {(n + 11) + (n + 10) + (n + 9) + (n + 8) + (n + 7) + (n + 6)}
Denominator is: {(n) + (n + 1) + ... + (n + 11)}
To Find: Determine the fraction of total interest owed.
Solution :
Numerator is: {(n + 11) + (n + 10) + (n + 9) + (n + 8) + (n + 7) + (n + 6)}
Since we are given that After the sixth month of a 12-month loan this becomes numerator .
So, put n = 6
Numerator = {(6 + 11) + (6 + 10) + (6 + 9) + (6 + 8) + (6 + 7) + (6 + 6)} = 87
Denominator : {(n) + (n + 1) + (n+2)+(n+3) +(n+4)+(n+5)+(n+6)+(n+7)+(n+8)+(n+9)+(n+10) + (n + 11)}
Put n =6
{(6) + (6 + 1) + (6+2)+(6+3) +(6+4)+(6+5)+(6+6)+(6+7)+(6+8)+(6+9)+(6+10) + (6+ 11)}
=138
Thus the fraction : \(\frac{Numerator}{Denominator} =\frac{87}{138} =\frac{29}{46}=0.6\)
