Answer: 0.24
Step-by-step explanation:
We use the formula ,
\(\text{Probability}=\dfrac{\text{favorable outcomes}}{\text{total outcomes}}\)
Given : A spinner has 10 equally sized sections, 4 of which are gray and 6 of which are blue.
Event 1 : spin lands on blue
\(P(E_1)=\dfrac{6}{10}\)
Event 2 : spin lands on gray
\(P(E_2)=\dfrac{4}{10}\)
Since both the events are independent of each other , then the probability that the first spin lands on blue and the second spin lands on gray will be :-
\(P(E_1)\times P(E_2)\\\\=\dfrac{6}{10}\times\dfrac{4}{10}=0.24\)
Hence, the probability that the first spin lands on blue and the second spin lands on gray = 0.24
