Verified Answer :

danceluv165

To solve this question you have to use the quadratic equation. So since the problem is already in standard form it will be pretty easy. So the quadratic equation is x=-b±√b²-4ac/2a. Not sure if it makes sense through a computer xD Anywho, you just have to input the values in the equation into the quadratic equation. From your problem a=3 b=6 and c=15. So just substitute those into the quadratic equation then simplify. In the end you should get -6±12i/6. Divide everything by 6 and you should get -1±2i!

The correct answer is -1±2i

The solution to the equation \(3x^2 + 6x + 15 = 0\) will be \(-1\pm 2i\) .

What is expression ?

Expressions is a finite combination of symbols that is well-formed according to rules that depend on the context.

We have,

\(3x^2 + 6x + 15 = 0\)

Now,

Taking \(3\) common we get,

\(x^2 + 2x + 5 = 0\)

Here, \(a=1,\)  \(b=2\),  \(c=5\)

Now,

Using the quadratic formula;

\(x=\frac{-b \pm \sqrt{ b^2-4ac}}{2a}\)

\(x=\frac{-2 \pm \sqrt{ 2^2-(4*1*5)}}{2*1}\)

\(x=\frac{-2 \pm \sqrt{ -16}}{2}\)

\(x=\frac{-2\ \pm\ (-4i)}{2}\)

\(x= -1\pm 2i\)

So, the solution of given equation is \(x= -1\pm 2i\) which is given in option (b).

Hence, we can say that the solution to the equation \(3x^2 + 6x + 15 = 0\) will be \(-1\pm 2i\) .

To know more about expression click here

https://brainly.com/question/14083225

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