y=-1/2(x+ 5)^2-2 Step by Step HELP
\(y=-\frac{1}{2}(x+5)^2-2\\ y=-\frac{1}{2}(x^2+10x+25-2)\\ y=-\frac{1}{2}(x^2+10x+23)\\\)this is not factorable so you must apply the quadratic formula and you'll end up with x=-5-2ix=-5+2i
frst opening formula : (a+b)^2=a^2+b^2+2ab=-1/2[x^2+25+10x]-2=-(x^2/2)-(25/2) -(5x)-(2) 0r =-1/2[x^2+25+10x+4] =-1/2[x^2+10x+29]
