Data:
Molar Mass of NaOH = 40 g/mol
Solving: According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules
1 mol -------------------- 6.0210²³ molecules
y mol -------------------- 2.7010²² molecules
6.0210²³y = 0.27010²³
\(y = \frac{0.270*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}{6.02*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}\)
\(\boxed{y \approx 0.04\:mol}\)
Solving: Find the mass value now
40 g ----------------- 1 mol of NaOH
x g ------------- 0.04 mol of NaOH
\(x = 40*0.04\)
\(\boxed{\boxed{x = 1.6\:g}}\end{array}}\qquad\quad\checkmark\)
Answer:
The mass is 1.6 grams
