Hello!
If the density of the mantle rock is about 3.3 g/cm3, then what is its specific gravity ?
A(2.6
B(3.0
C(3.3
D(2.8
Solving:
To find specific gravity, we must divide the density of the mantle rock (3.3 g/cm³) by the density of the water (1 g/cm³), let's see:
\(Specific\:gravity = \dfrac{3.3\:g/cm^3}{1\:g/cm^3}\)
\(\boxed{\boxed{Specific\:gravity = 3.3}}\end{array}}\qquad\checkmark\)
Answer:
C(3.3
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I Hope this helps, greetings ... Dexteright02! =)
