Answer:
The required order of polynomial is \(-4r^3s-3r^2+2rs-5\).
Step-by-step explanation:
The given polynomial is
\(2rs-5-3r^2-4r^3s\)
We have to arrange the polynomial in descending powers of r.
In term 2rs, the power of r is 1.
In term -5, the power of r is 0.
In term -3r², the power of r is 2.
In term -4r³s, the power of r is 3.
On arranging the polynomial in descending powers of r, we get
\(-4r^3s-3r^2+2rs-5\)
Therefore the required order of polynomial is \(-4r^3s-3r^2+2rs-5\).
