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NoelaniNadia
NoelaniNadia NoelaniNadia
  • 24-02-2017
  • Mathematics
Answered

Simplify: x^0 y^-3 / x^2 Y^-1

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Verified Answer :

Anonymous Anonymous
  • 24-02-2017

x^0 y^-3 / x^2 y^-1 
= 1 / 
 x^2 y^-1 (y^3)  ...because  x^0 = 1 and  [(y^-1) (y^3)] = y^2
= 1/(x^2 y^2)

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12150286
12150286 12150286
  • 24-02-2017

But if you're adding them the answer would be \(1/ x^{2}y^2\)

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