Let an integer be chosen at random from the integers 1 to 30 inclusive. Find the probability that the integer chosen is not evenly divisible by 2.
Exactly half of these integers are odd (1, 3, 5, ..., 29) so the probability of selecting an odd number is \(\dfrac12\).
Answer:
probability that the integer not evenly divisible by 2 is \(\frac{1}{2}\).
Step-by-step explanation:
Given : An integer be chosen at random from the integers 1 to 30 inclusive.
To find : Find the probability that the integer chosen is not evenly divisible by 2.
Solution : We have integers 1 to 30.
We need to find probability that the integer not evenly divisible by 2.
We know that odd numbers are not divisible by 2
Odd number 1 to 30 ( 1 , 3, 5, 7 ,9,11,13,15,17,19,21,23,25,27,29)
Total odd number 1 to 30 = 15 .
Probability = \(\frac{favourble\ outcome}{total\ numver\ of\ outcome}\).
Probability = \(\frac{15}{30}\).
Probability = \(\frac{1}{2}\).
Therefore, probability that the integer not evenly divisible by 2 is \(\frac{1}{2}\).